Meter Bridge

In a meter bridge balance point is found at a distance  $l_1$  with resistances R and S as shown in the figure.



When an unknown resistance X is connected in parallel with the resistance S, the balance point shifts to a distance $l_2$ . Find the expression for X in terms of  $l_1$ ,  $l_2$  and S.

$AB$ is a uniform wire of meter bridge, across which an ideal $20 \mathrm{volt}$ cell is connected as shown. Two resistor of $1 \mathrm{\Omega }$ and $X \mathrm{\Omega }$ are inserted in slots of metre bridge. A cell of emf $E \mathrm{volts}$ and internal resistance $r \mathrm{\Omega }$ and a galvanometer is connected to jockey $J$ as shown.

If $E=16 \mathrm{volts}$, $r= 4 \mathrm{\Omega }$ and the distance of balance point $P$ from end $A$ is $90 \mathrm{cm}$, then the value of $X$ is

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The sensitivity of the meter bridge is at the peak when all resistors have the same order.

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Figure shows a Meter bridge wire $AC$ has uniform cross-section. The length of wire $AC$ is $100 \mathrm{cm}$ $X$ is a standard resistor of $4 \mathrm{\Omega }$ and $Y$ is a coil. When $Y$ is immersed in melting ice the null point is at $40 \mathrm{cm}$ from point $A$. When the coil $Y$  is heated to $100°\mathrm{C},$ a $12 \mathrm{\Omega }$ resistor has to beconnected in parallel with $Y$ in order to keep the bridge balanced at the same point. The temperature coefficient of resistance of the coil is $x\times {10}^{-2} \mathrm{SI}$ units. Find the value of $x$.

Consider the meter bridge circuit without neglecting end corrections. If we used $100 \mathrm{\Omega }$ and $200 \mathrm{\Omega }$ resistance in place of $R$ and $S$ respectively, we get null deflection at $l_1=33.0 \mathrm{cm}$. If we interchange the resistances, the null deflection was found to be at $l_2=67.0 \mathrm{cm}$. If $\alpha$ and $\beta$ are the end correction, then the value of $\alpha +\beta$ should be

If the wire in the experiment to determine the resistivity of a material using metre bridge is replaced by copper or hollow wire the balance point i.e. null point shifts to

Null method is superior over deflection method because

Where do we get the balancing point of the meter bridge generally?